Algebra

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Tutors/teachers:

Nikkolas

Tutor and Aerospace Engineer

# Difference of Squares

#### Lesson Contents

## The Difference of Squares Pattern

There are special patterns that some polynomials follow. **The difference of squares pattern is when a polynomial is made up of a square minus another square.** This pattern allows us to easily factor the polynomial. The formula is given as:*a ^{2} – b^{2} = (a + b)(a – b)*

Where *a* and *b* may be any algebraic expression. For example, *a* could be a variable such as “y”, and *b* could be a number such as “5”. Or, *a* could be a more complicated expression such as “2x^{3}“. The difference of squares pattern can be used for any set of algebraic expressions.

### When to use the Difference of Squares

The difference of squares pattern comes in handy when we must factor a polynomial to find the roots/zeros or to simplify it. For example, we might be tasked with finding the roots/zeros of the equation y = x^{2} – 9.

We can use the difference of squares to factor the right-hand side of the equation and then find the roots/zeroes. Applying the difference of squares pattern to x^{2} – 9 gives us (x + 3)(x – 3). Using this factored form, we can determine that the roots/zeros are x = -3 and x = 3.

### Example Problems

Problem 1:

Using the difference of squares pattern, factor the polynomial x^{2} – 49.

Solution:

1.) Let’s set a = x and b = 7 because a^{2} = x^{2} and b^{2} = 49.

2.) Applying the pattern (a + b)(a – b), we get (x + 7)(x – 7).**The factored form of the polynomial x ^{2} – 49 is (x + 7)(x – 7).**

Problem 2:

Find the x-intercepts of y = 4x^{4} – 64.

Solution:

1.) We find the x-intercepts by setting y = 0. This gives us 0 = 4x^{4} – 64.

2.) We must now find the zeroes of the expression 4x^{4} – 64. The expression is a difference of squares binomial.

3.) Applying the formula, we get:

a^{2} – b^{2} = (a + b)(a – b)

4x^{4} – 64 = (2x^{2} + 8)(2x^{2} – 8)

4.) Now that it’s in factored form, we can find the zeroes. (2x^{2} + 8)(2x^{2} – 8) has zeroes at x = 2 and x = -2.**The x-intercepts are located at x = 2 and x = -2.**

Result :

Worksheet 1

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Cheat sheet

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